3.644 \(\int \frac {(c x)^{3/2}}{(3 a-2 a x^2)^{3/2}} \, dx\)

Optimal. Leaf size=94 \[ \frac {c \sqrt {c x}}{2 a \sqrt {3 a-2 a x^2}}-\frac {c^{3/2} \sqrt {3-2 x^2} \operatorname {EllipticF}\left (\sin ^{-1}\left (\frac {\sqrt [4]{\frac {2}{3}} \sqrt {c x}}{\sqrt {c}}\right ),-1\right )}{2 \sqrt [4]{6} a \sqrt {a \left (3-2 x^2\right )}} \]

[Out]

-1/12*c^(3/2)*EllipticF(1/3*2^(1/4)*3^(3/4)*(c*x)^(1/2)/c^(1/2),I)*(-2*x^2+3)^(1/2)*6^(3/4)/a/(a*(-2*x^2+3))^(
1/2)+1/2*c*(c*x)^(1/2)/a/(-2*a*x^2+3*a)^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.05, antiderivative size = 94, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {288, 329, 224, 221} \[ \frac {c \sqrt {c x}}{2 a \sqrt {3 a-2 a x^2}}-\frac {c^{3/2} \sqrt {3-2 x^2} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{\frac {2}{3}} \sqrt {c x}}{\sqrt {c}}\right )\right |-1\right )}{2 \sqrt [4]{6} a \sqrt {a \left (3-2 x^2\right )}} \]

Antiderivative was successfully verified.

[In]

Int[(c*x)^(3/2)/(3*a - 2*a*x^2)^(3/2),x]

[Out]

(c*Sqrt[c*x])/(2*a*Sqrt[3*a - 2*a*x^2]) - (c^(3/2)*Sqrt[3 - 2*x^2]*EllipticF[ArcSin[((2/3)^(1/4)*Sqrt[c*x])/Sq
rt[c]], -1])/(2*6^(1/4)*a*Sqrt[a*(3 - 2*x^2)])

Rule 221

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Simp[EllipticF[ArcSin[(Rt[-b, 4]*x)/Rt[a, 4]], -1]/(Rt[a, 4]*Rt[
-b, 4]), x] /; FreeQ[{a, b}, x] && NegQ[b/a] && GtQ[a, 0]

Rule 224

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> Dist[Sqrt[1 + (b*x^4)/a]/Sqrt[a + b*x^4], Int[1/Sqrt[1 + (b*x^4)
/a], x], x] /; FreeQ[{a, b}, x] && NegQ[b/a] &&  !GtQ[a, 0]

Rule 288

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^
n)^(p + 1))/(b*n*(p + 1)), x] - Dist[(c^n*(m - n + 1))/(b*n*(p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^(p + 1), x
], x] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0] && LtQ[p, -1] && GtQ[m + 1, n] &&  !ILtQ[(m + n*(p + 1) + 1)/n, 0]
&& IntBinomialQ[a, b, c, n, m, p, x]

Rule 329

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + (b*x^(k*n))/c^n)^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rubi steps

\begin {align*} \int \frac {(c x)^{3/2}}{\left (3 a-2 a x^2\right )^{3/2}} \, dx &=\frac {c \sqrt {c x}}{2 a \sqrt {3 a-2 a x^2}}-\frac {c^2 \int \frac {1}{\sqrt {c x} \sqrt {3 a-2 a x^2}} \, dx}{4 a}\\ &=\frac {c \sqrt {c x}}{2 a \sqrt {3 a-2 a x^2}}-\frac {c \operatorname {Subst}\left (\int \frac {1}{\sqrt {3 a-\frac {2 a x^4}{c^2}}} \, dx,x,\sqrt {c x}\right )}{2 a}\\ &=\frac {c \sqrt {c x}}{2 a \sqrt {3 a-2 a x^2}}-\frac {\left (c \sqrt {3-2 x^2}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-\frac {2 x^4}{3 c^2}}} \, dx,x,\sqrt {c x}\right )}{2 \sqrt {3} a \sqrt {a \left (3-2 x^2\right )}}\\ &=\frac {c \sqrt {c x}}{2 a \sqrt {3 a-2 a x^2}}-\frac {c^{3/2} \sqrt {3-2 x^2} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{\frac {2}{3}} \sqrt {c x}}{\sqrt {c}}\right )\right |-1\right )}{2 \sqrt [4]{6} a \sqrt {a \left (3-2 x^2\right )}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [C]  time = 0.02, size = 59, normalized size = 0.63 \[ -\frac {c \sqrt {c x} \left (\sqrt {9-6 x^2} \, _2F_1\left (\frac {1}{4},\frac {1}{2};\frac {5}{4};\frac {2 x^2}{3}\right )-3\right )}{6 a \sqrt {a \left (3-2 x^2\right )}} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*x)^(3/2)/(3*a - 2*a*x^2)^(3/2),x]

[Out]

-1/6*(c*Sqrt[c*x]*(-3 + Sqrt[9 - 6*x^2]*Hypergeometric2F1[1/4, 1/2, 5/4, (2*x^2)/3]))/(a*Sqrt[a*(3 - 2*x^2)])

________________________________________________________________________________________

fricas [F]  time = 0.69, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {-2 \, a x^{2} + 3 \, a} \sqrt {c x} c x}{4 \, a^{2} x^{4} - 12 \, a^{2} x^{2} + 9 \, a^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^(3/2)/(-2*a*x^2+3*a)^(3/2),x, algorithm="fricas")

[Out]

integral(sqrt(-2*a*x^2 + 3*a)*sqrt(c*x)*c*x/(4*a^2*x^4 - 12*a^2*x^2 + 9*a^2), x)

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (c x\right )^{\frac {3}{2}}}{{\left (-2 \, a x^{2} + 3 \, a\right )}^{\frac {3}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^(3/2)/(-2*a*x^2+3*a)^(3/2),x, algorithm="giac")

[Out]

integrate((c*x)^(3/2)/(-2*a*x^2 + 3*a)^(3/2), x)

________________________________________________________________________________________

maple [A]  time = 0.04, size = 126, normalized size = 1.34 \[ \frac {\sqrt {c x}\, \sqrt {-\left (2 x^{2}-3\right ) a}\, \left (-12 x +\sqrt {\left (2 x +\sqrt {2}\, \sqrt {3}\right ) \sqrt {2}\, \sqrt {3}}\, \sqrt {\left (-2 x +\sqrt {2}\, \sqrt {3}\right ) \sqrt {2}\, \sqrt {3}}\, \sqrt {-\sqrt {2}\, \sqrt {3}\, x}\, \EllipticF \left (\frac {\sqrt {3}\, \sqrt {2}\, \sqrt {\left (2 x +\sqrt {2}\, \sqrt {3}\right ) \sqrt {2}\, \sqrt {3}}}{6}, \frac {\sqrt {2}}{2}\right )\right ) c}{24 \left (2 x^{2}-3\right ) a^{2} x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^(3/2)/(-2*a*x^2+3*a)^(3/2),x)

[Out]

1/24*c*(c*x)^(1/2)*(-(2*x^2-3)*a)^(1/2)*(((2*x+2^(1/2)*3^(1/2))*2^(1/2)*3^(1/2))^(1/2)*((-2*x+2^(1/2)*3^(1/2))
*2^(1/2)*3^(1/2))^(1/2)*(-2^(1/2)*3^(1/2)*x)^(1/2)*EllipticF(1/6*3^(1/2)*2^(1/2)*((2*x+2^(1/2)*3^(1/2))*2^(1/2
)*3^(1/2))^(1/2),1/2*2^(1/2))-12*x)/x/a^2/(2*x^2-3)

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (c x\right )^{\frac {3}{2}}}{{\left (-2 \, a x^{2} + 3 \, a\right )}^{\frac {3}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^(3/2)/(-2*a*x^2+3*a)^(3/2),x, algorithm="maxima")

[Out]

integrate((c*x)^(3/2)/(-2*a*x^2 + 3*a)^(3/2), x)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (c\,x\right )}^{3/2}}{{\left (3\,a-2\,a\,x^2\right )}^{3/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^(3/2)/(3*a - 2*a*x^2)^(3/2),x)

[Out]

int((c*x)^(3/2)/(3*a - 2*a*x^2)^(3/2), x)

________________________________________________________________________________________

sympy [A]  time = 2.10, size = 51, normalized size = 0.54 \[ \frac {\sqrt {3} c^{\frac {3}{2}} x^{\frac {5}{2}} \Gamma \left (\frac {5}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {5}{4}, \frac {3}{2} \\ \frac {9}{4} \end {matrix}\middle | {\frac {2 x^{2} e^{2 i \pi }}{3}} \right )}}{18 a^{\frac {3}{2}} \Gamma \left (\frac {9}{4}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)**(3/2)/(-2*a*x**2+3*a)**(3/2),x)

[Out]

sqrt(3)*c**(3/2)*x**(5/2)*gamma(5/4)*hyper((5/4, 3/2), (9/4,), 2*x**2*exp_polar(2*I*pi)/3)/(18*a**(3/2)*gamma(
9/4))

________________________________________________________________________________________